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Mathematics 23 Online
OpenStudy (moongazer):

finding x in complex numbers examples?

OpenStudy (anonymous):

like?

OpenStudy (anonymous):

comparing the real and complex parts?

OpenStudy (anonymous):

moongazer can u please reply?

OpenStudy (anonymous):

Yeah we need specifics on this

OpenStudy (anonymous):

MOONGAZER

OpenStudy (moongazer):

like 7i + 56+ 3x=9+7x -3+7y something like that because i just saw it on my test paper and the teacher did not teach it, so it became a bonus. I just want studying in advance I forgot the exact question on the the paper but I think it is something like that ^_^

OpenStudy (anonymous):

r u sure thers no iota on the right side?

OpenStudy (moongazer):

i don't know

OpenStudy (moongazer):

maybe there is

OpenStudy (moongazer):

is the iota the letter i ???

OpenStudy (moongazer):

like thingy used in imaginary numbers?

OpenStudy (anonymous):

yes

OpenStudy (moongazer):

so how do you find x? or y?

OpenStudy (anonymous):

Basically, you just follow the usual way of doing things but take account of the possible manipulations of i whereby you might be able to get rid of it altogether.

OpenStudy (moongazer):

so it is just like x+2=2x-1 is 3=x ???

OpenStudy (anonymous):

Yup, 2i + i = 3i, no surprises there either. Getting rid of i altogether will usually require multiplying it by another i so as to produce i^2 = -1.

OpenStudy (moongazer):

or 2i+x+2=10 is x=8-2i is it just like that?

OpenStudy (anonymous):

Yep.

OpenStudy (anonymous):

Which you can read as x is the complex number 8 minus 2i.

OpenStudy (moongazer):

ok I thought it is different ^_^

OpenStudy (anonymous):

You can think of an ordinary number as being (thenumber) + 0i

OpenStudy (moongazer):

yup, thanks!

OpenStudy (moongazer):

You leveled up so fast estudier, as i remember, the first time you answered one of my question your level is just one digit. Maybe you are intelligent or already in a higher education. ^_^

OpenStudy (anonymous):

Old guy, know a lot about a little and a little about a lot. (I have a degree in Math and Computing as well, which helps)

OpenStudy (radar):

These relations should prove hel\[-i ^{2}=1\]pful working with "i" \[i=\sqrt{-1}\]\[i ^{2}=-1\]\[i ^{3}=-\sqrt{-1}\]\[i ^{4}=1\]

OpenStudy (moongazer):

i know that ^_^

OpenStudy (radar):

ignore the typo, good, you will be using that info when you rationalize complex numbers etc.

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