Question

I am trying to simplify this :
2(x-1)(x+1)^2+2(x+1)(x-1)^2

Answer 1

\[4(x-1)^{2}\]

Answer 2

2(x-1)(x+1)[(x+1)+(x-1)]
2(x-1)(x+1)(2x)

Answer 3

but where do the squares go

Answer 4

mathstud did you ever look at my attachment about this problem
i already simplied it for you

Answer 5

i just dont understand you got rid of the squares

Answer 6

i factored out (x+1) and (x-1)

Answer 7

i also factored out a 2

Answer 8

can you post that doc again? please

Answer 9

4x(x-1)^2

Answer 10

thanks

Answer 11

2x^2y+2xy^2
we can factor this right?
both terms have a 2, and a x, and a y in common
so we have 2x^2y+2xy^2=2xy(x+y)

Answer 12

(x-1)(x+1) = (x^2-1) can be factored.

Answer 13

yes x^2-1 can be factorer
its factors are x-1 and x+1 gj

Answer 14

u get it, mathstud?

Answer 15

I mean, do you see where the squares go?

Answer 16

Gone away to study it...

Answer 17

hey, why is there a max at 1 and a min 0

Answer 18

I got x=1, x=-1, and x=0

Answer 19

i got a max at x=0
and a min at x=1 and x=-1

Answer 20

It's 4x(x-1)^2 so x=0 and 1(repeated).

Answer 21

estudier
its suppose to be 4x(x^2-1)
or 4x(x-1)(x+1)

Answer 22

Oops, sorry...(beg for forgiveness)

Answer 23

0 and +-1 looks good...