Determine if the following is exact and solve it
where is the eqn?
\[( x dx / (x ^{2} + y^{2})^{3/2}) + ( y dy / (x ^{2} + y^{2})^{3/2}) = 0\]
okay working this out on paper..
watch out.. be sure if its exact or not
it's not exact.
wait a second sorry.. i was wrong..
It is exact, because My = Nx = (-3xy)/(x^2+y^2)^(5/2)
so: Fx = M = x/(x^2+y^2)^(3/2); F(x;y) = Integral of x/(x^2+y^2)^(3/2) dx = [ -1/sqrt(x^2+y^2) ] + h(y)
how did u knw the My (or the Nx) ??? i cant rearrange it to the standard form
it is already in standard form...
Grrrrrrrr... how come
where is the Y prime ? \[Y \prime\]
it is in the form: Mdx + Ndy=0 M = x/(x^2+y^2)^(3/2) (first section without the dx) N = y/(x^2+y^2)^(3/2) (2nd part without the dy) see..
That is all you need to determine if it is exact or not..
So once you have the M and N, if Mx (derivative of M with respect to x) = Ny (derivative of N with respect to y), then your equation is exact.
Lifesaver :) Thanx a lot Bro
np... lol..
I'm actually a superstar on my other account lol.. i got tired of it.. this is bahrom7893
take a look @ my other question
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