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Mathematics 16 Online
OpenStudy (deez):

Determine if the following is exact and solve it

OpenStudy (anonymous):

where is the eqn?

OpenStudy (deez):

\[( x dx / (x ^{2} + y^{2})^{3/2}) + ( y dy / (x ^{2} + y^{2})^{3/2}) = 0\]

OpenStudy (anonymous):

okay working this out on paper..

OpenStudy (deez):

watch out.. be sure if its exact or not

OpenStudy (anonymous):

it's not exact.

OpenStudy (anonymous):

wait a second sorry.. i was wrong..

OpenStudy (anonymous):

It is exact, because My = Nx = (-3xy)/(x^2+y^2)^(5/2)

OpenStudy (anonymous):

so: Fx = M = x/(x^2+y^2)^(3/2); F(x;y) = Integral of x/(x^2+y^2)^(3/2) dx = [ -1/sqrt(x^2+y^2) ] + h(y)

OpenStudy (deez):

how did u knw the My (or the Nx) ??? i cant rearrange it to the standard form

OpenStudy (anonymous):

it is already in standard form...

OpenStudy (deez):

Grrrrrrrr... how come

OpenStudy (deez):

where is the Y prime ? \[Y \prime\]

OpenStudy (anonymous):

it is in the form: Mdx + Ndy=0 M = x/(x^2+y^2)^(3/2) (first section without the dx) N = y/(x^2+y^2)^(3/2) (2nd part without the dy) see..

OpenStudy (anonymous):

That is all you need to determine if it is exact or not..

OpenStudy (anonymous):

So once you have the M and N, if Mx (derivative of M with respect to x) = Ny (derivative of N with respect to y), then your equation is exact.

OpenStudy (deez):

Lifesaver :) Thanx a lot Bro

OpenStudy (anonymous):

np... lol..

OpenStudy (anonymous):

I'm actually a superstar on my other account lol.. i got tired of it.. this is bahrom7893

OpenStudy (deez):

take a look @ my other question

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