I had a question, i was reading in my calc book the chp on curve tracing, and it made a statement i quite don't comprehend fully. It said that when y' is 0 we do not know whether y is increasing or decreasing. And then it said that when y' is 0 usually y has a rel. max/min. I am confused because i thought that when a graph as a rel. max/min we could determine whether that function is increasing or decreasing when or at the points where the derivative is 0. could someone clarify?
usually to determine concavity look at y''. If y'' >0. y' is increasing, rel min y'' <0 . y' is decreasing, rel max
but when y' is zero, we can dtermine if a function is increasing or decreasing correct?
true, thats why we look at y'' for x=1, say y'=0 well at x=1, y'' = -2 this tells us we have a rel max, function is going from increasing to decreasing
okay
you can also evaluate at points less than critical point to determine increasing/decreasing so at x=1, y'=0, y=5 look at x=0, say y' = 3, y=3 then y is increasing, y' is decreasing thus rel max
critical points would be where the derivative is 0 right?
yes
it depends on the function, if it it easily differentiable, take 2nd derivative otherwise use other approach
let me asking you something else, regarding abso and rel max and min. Lets say i have a cubic function and the derivative was 0 at x=1 and x=3. And i determined that that function has a rel max of 3(1/3) at x=1. But now i want to use an interval of [0,3], why does my book say that the abso. max is still 3(1/3), and that there are abso. min values at two locations 0 and 3.
because you have restricted the domain, the section of graph from [0,3] has abs min at 0,3 and abs max at 1 however that is not true for the function just the part of the graph from [0,3]
its like you defined a new function, where 0<x<3
When it comes to working with a closed interval, my book says that the absolute mx and min must occur at either on or both ends of the intervlal or it must occur at some value of x within the interval. Now, does that mean, that if i have determed that there is a rel. max or min, at an interrior point, lets say that [0,3], x=2, then that y value at x=2 would be the abso. max or min as well as the rel max or min?
yes, many times the rel max/min is the abs max/min in a specified interval but it depends on the interval
for example if the interval is wide enough it may be the end point has larger y value than the rel max, thus the abs max would be the end point
So i should evlaute both the endpoint of the interval. Now what happens if the derivatve of a function is 0 at point within the interval and i determined that at either one of these points there is a max or min. Noe would i still need to check the endpoints?
oh okay, so if i found that the derivative is zero at interior points and i determined that they give me a max or min, but then i also evaluate the endpoint, and find that the endpoint give me higher (max) or lower(min) values, these would then be the abso max/min
yes
I appreciate your patience, i am taking calc over the summer so that i can finish up my 2 years at community college quicker and that why i am asking these questions. Thanks again.
no problem, good luck with your class
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