Question

Convert the following equation from rectangular to polar form: y = x^2

Answer 1

y=rsin(theta)
x=xcos(theta)
So:
rsin(theta)=r^2cos^2(theta)

Answer 2

r=cot(theta)csc(theta)

r =tan(theta)sec(theta)

r =tan(theta)

r = cot(theta)

those are the answer choices

Answer 3

\[r=\sqrt{x ^{2}+y ^{2}} \]
\[\tan \theta=y/x\]

Answer 4

You want to divide out the common factor of r giving:
sin(theta)=rcos^2(Theta)
Divide over the cos^2(theta)
sin(theta)/cos(theta)*(1/cos(theta))=r
so r=tan(theta)sec(theta)

Answer 5

So \[\tan \theta=x ^{2}/x=x\]

Answer 6

now \[r=\sqrt{x ^{2}+x ^{4}} = x \sqrt{1+x ^{2}}\]

Answer 7

or
\[r=\tan \theta \sqrt{1+\tan ^{2}\theta}\]

Answer 8

now I suppose it can be simplified to an answer

Answer 9

Of:
\[r=\tan(\theta)\sec(\theta)\]