One More Question:
Find the difference quotient of f for this function:

f(x) = 1
----
x + 2

(can you also put a breakdown of how you got the answer? )

Question

One More Question:
Find the difference quotient of f for this function:

f(x) = 1
       ----
        x + 2

(can you also put a breakdown of how you got the answer? )

anonymous · Answer

i gues you will differentiate

anonymous · Answer

?

dumbcow · Answer

$$=\frac{\frac{1}{(x+h)+2} - \frac{1}{x+2}}{h}$$

dumbcow · Answer

$$=\frac{\frac{x+2 - (x+h+2)}{(x+2)(x+h+2)}}{h} = \frac{-h}{h(x+2)(x+h+2)}$$

dumbcow · Answer

cancel the h's and then it is simplified

anonymous · Answer

follow dumbcows order thaz wat i mean

dumbcow · Answer

when h=0 , it gives the derivative
so mathfrick was right, you just haven't got to that step yet

anonymous · Answer

do I have to breakdown the denominator and distribut h before i simplify? i can't seem to get the right answer

dumbcow · Answer

no need to distribute, h/h = 1

dumbcow · Answer

= -1/(x+2)(x+h+2)

anonymous · Answer

that's the answer?

dumbcow · Answer

yes, the answer is just using the def they gave you f(x+h) -f(x)/h
all i did was combine fractions and simplified