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Mathematics 10 Online
OpenStudy (anonymous):

What is the integral of arcsin(x)?

OpenStudy (anonymous):

1/sqrt(1-x^2)

OpenStudy (anonymous):

Okay thanks.

OpenStudy (anonymous):

Not true^^ You have to do integration by parts. Let u=arcsin(x) and dv=dx Then du=1/sqrt(1-x^2)dx and v=x Then you have: \[x \arcsin(x)-\int\limits \frac{x dx}{\sqrt{1-x^2}}\] From here it is a u-sub.

OpenStudy (anonymous):

OH SNAP SORRY I SAID DERIVATIVE OD ARCSIN!...

OpenStudy (anonymous):

*of.. my bad malevolence is correct..

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