Question

The flower garden has the shape of a right triangle. 15ft of a perennial border forms the hypotenuse of the triangle, and one leg is 3ft longer than other leg. Find the lengths if the legs.


What are the lengths of the legs? ?=ft please

Answer 1

Please help me someone!

Answer 2

So we know the length of the hypotenuse, so call the two remaining side lengths A and B.
Then, A=B+3
And, 15^2=A^2+B^2 by Pythagorean thm
Solve for one of the variables, and sub into the second equation...

Just ask for more help!

Answer 3

I am trying to finish a few more question but I can seem to get this one worked out can I get more like the answer please by any chance

Answer 4

If we substitute in the first equation into the second in terms of A, we have
15^2=(B+3)^2+B^2
So, you'll need to expand the (B+3)^2 (FOILing) and then solve for B. It'll be a quadratic so you'll need to factor, or complete the square or use the formula. Give it a try and let me know what you end up with.

Answer 5

the length of the legs are 6 and 9

using the pythagorean theorem ( \[a^{2} + b^{2} = c^{2}\])
15=c(hypotenuse)

( 3+L )^{2} + L^{2} = 15^{2}
\[\sqrt{( 3+L )^{2} + L^ {2} = 15^{2}}\]
3 + L + L = 15
2L =15-3
2L = 12
L=6

for the other leg = 3+L
3 + 6 = 9

so, 6 and 9 are the lengths of the legs.:)) i hope my answer is correct..:)

Answer 6

6ft and 9ft