what is the limit of LN x / x
use l'hopital's rule to get 0
for x=zero this function is undefined
fraction with denominator zero ... interesantly
sorry .. i thought the limit was to infinity.
evern indifferent when we have one equation with fraction the first condition, substitution is that the denominator not can being zero
may be it is like this..lim [ x - ln(x) ] x -> infinity As you already know, this is in the form infinity - infinity, so we have to change its form. One thing you can do is change the form of x to ln(e^x), because ln and e are inverses of each other and x = ln(e^x). lim [ ln(e^x) - ln(x) ] x -> infinity Now, we can combine the logs as per the identity. lim [ ln( e^x / x ) ] x -> infinity And we can move the limit inside the log. ln [ lim (e^x / x ) ] . . . x -> infinity And now we can apply L'Hospital's rule. ln [ lim ( e^x / 1 ) ] . . . x -> infinity ln [ lim ( e^x ) ] . . . x -> infinity As x approaches infinity, e^x approaches infinity. As e^x approaches infinity, so does ln(e^x). Therefore, the answer is infinity.
^ wasnt what the question was asking for , but something a little different
the limit does not exist! lol i just remembered the movie of lindsay lohan "mean girls" just sharing. hahaha
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