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Mathematics 13 Online
OpenStudy (anonymous):

what is the limit of LN x / x

OpenStudy (anonymous):

use l'hopital's rule to get 0

jhonyy9 (jhonyy9):

for x=zero this function is undefined

jhonyy9 (jhonyy9):

fraction with denominator zero ... interesantly

OpenStudy (anonymous):

sorry .. i thought the limit was to infinity.

jhonyy9 (jhonyy9):

evern indifferent when we have one equation with fraction the first condition, substitution is that the denominator not can being zero

OpenStudy (anonymous):

may be it is like this..lim [ x - ln(x) ] x -> infinity As you already know, this is in the form infinity - infinity, so we have to change its form. One thing you can do is change the form of x to ln(e^x), because ln and e are inverses of each other and x = ln(e^x). lim [ ln(e^x) - ln(x) ] x -> infinity Now, we can combine the logs as per the identity. lim [ ln( e^x / x ) ] x -> infinity And we can move the limit inside the log. ln [ lim (e^x / x ) ] . . . x -> infinity And now we can apply L'Hospital's rule. ln [ lim ( e^x / 1 ) ] . . . x -> infinity ln [ lim ( e^x ) ] . . . x -> infinity As x approaches infinity, e^x approaches infinity. As e^x approaches infinity, so does ln(e^x). Therefore, the answer is infinity.

OpenStudy (anonymous):

^ wasnt what the question was asking for , but something a little different

OpenStudy (anonymous):

the limit does not exist! lol i just remembered the movie of lindsay lohan "mean girls" just sharing. hahaha

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