Question

lim square root of z^2-64 divide z-64
if z is equal to 4

Answer 1

\[\lim_{z = 4} \sqrt{z^2-64}\div z-64\]
Is this what you meant?

Answer 2

we are getting an imaginary answer here if we go by gripphe s method

Answer 3

\[-\frac{i}{5 \sqrt{3}} \]

Answer 4

limit sqrt (z+8) z to 4 is 2 sqrt 3.

Answer 5

\[\text{Limit}\left[\frac{\sqrt{z^2-64}}{z-64},z\to 4\right]=-\frac{i}{5 \sqrt{3}} \]

Answer 6

There's a few like this, think the square root is supposed to over everything.

Answer 7

\[\text{Limit}\left[\sqrt{\frac{z^2-64}{z-64}},z\to 4\right]=\frac{2}{\sqrt{5}} \]

Answer 8

Duh!:-)

Answer 9

A Mathematica solution. If it is incorrect, I believe Wolfram Research would like to know about it.