Question

Two planes which are 1820 miles apart, fly toward each other. Their speeds differ by 60 mph. If they pass each other in 2 hours, what is the speed of each?

Answer 1

d= rt
2r + 2(r+60) = 1820

Answer 2

4r + 120 = 1820
4r = 1820 -120

Answer 3

r = 425

Answer 4

and second plane has 485

Answer 5

Alright, lets get some equations down using that data:
The distance each plane is going to fly is going to be its velocity times 2 hours (they will both be flying for 2 hours. So we have:
\[d_1=v_1(2), d_2=v_2(2)\]
Let v1 be the velocity of the slower plane. Then v2 is:
\[v_2 = v_1+60\]
also, their distances must add up to 1820, so now we have:
\[1820 = v_1(2)+(v_1+60)(2) \Rightarrow v_1 = \frac{1820-120}{4} = 425mph\]
That is the slower plane, add 60 to get the faster plane going at 485 mph.