Question

how do you find the product (-1/3x^2-1/3)(1/2x+1/4)

Answer 1

Do you know how to factor?

Answer 2

not sure

Answer 3

\[\bigg(\frac{1}{3}x^{2}-\frac{1}{3} \bigg) \bigg(\frac{1}{2}x+\frac{1}{4} \bigg)\]

Is it right?

Answer 4

(-1/3x^2-1/3)(1/2x+1/4)

Answer 5

OK, just the minus in front of first bit, yes?

Answer 6

yes

Answer 7

\[\bigg(-\frac{1}{3}x^{2}-\frac{1}{3} \bigg) \bigg(\frac{1}{2}x+\frac{1}{4} \bigg)\]

Answer 8

yes

Answer 9

By factor, I mean to take out a common piece from inside a bracket...

Answer 10

So we could take out the -1/3 from the first bracket for instance.

Answer 11

and combine it with the 1/2 in the second bracket

Answer 12

I combined using FOIL and ended up with 1/6x^2 - 1/12 + 1/12

Answer 13

\[-\frac{1}{3}\bigg (x^{2}+1 \bigg) \bigg(\frac{1}{2}x+\frac{1}{4} \bigg)\]

Like this...

Answer 14

1/6x^2-1/12 +1/6 - 1/12

Answer 15

I don't understand where u got the above?

Answer 16

not sure either

Answer 17

Do you think you could do the same thing as I did with the -1/3, only do it with the second bracket and take out 1/4?

Answer 18

yes i think I can... I will try and see what happens. thanks for the help

Answer 19

\[-\frac{1}{3}\bigg (x^{2}+1 \bigg) \dfrac{1}{4} \bigg(2x+1 \bigg)\]

Answer 20

Now it's easier , right?

Answer 21

yes it is ... thanks

Answer 22

ur welcome.