Write a quadratic equation in the variable x having the give numbers as solution. Type the equation in standard form, ax^2+ bx+c=0

solution:10, only solution

Question

Write a quadratic equation in the variable x having the give numbers as solution. Type the equation in standard form, ax^2+ bx+c=0

solution:10, only solution

llort · Answer

pardon? was this cut off?

dumbcow · Answer

y = (x-10)^2 --> x^2 -20x + 100 = 0

llort · Answer

now I see it, there is only one intersect, (x+10)(x+10)

X^2+20X+100=0

anonymous · Answer

dumbcow got it.  If the quadratic only had 10 as a solution, when factored it would have to be:
$$(x-10)(x-10) = (x-10)^{2} = x^{2}-20x+100$$

llort · Answer

yep, the methane producing cud-chewer got it again...

anonymous · Answer

same but 3, only solution please

dumbcow · Answer

just plug in 3 where 10 was before :)

llort · Answer

(x+3)(x+3)

go from there...

anonymous · Answer

its (x - 3)(x - 3)

llort · Answer

give a man a fish, he'll eat for a day; teach a man to fish, he'll eat for a lifetime.

anonymous · Answer

x^2-30x+1000

anonymous · Answer

is that correct

llort · Answer

remember FOIL

First
Outside
Inside
Last

anonymous · Answer

(x-3)(x-3)=(x-3)^2=(x-3)^2-6x+9 is that correct

llort · Answer

First:

x*x=x^2

Outside:

x*-3=-3x

Inside:

-3*x=-3x

Last:

-3*-3=9

now you have:

x^2-3x-3x+9

Which can simplify to:

x^2-6x+9

llort · Answer

do you get it?