$18,887 is invested, part at 14% and the rest at 8%. If the interest earned from the amount invested at 14% exceeds the interest earned from the amount invested at 8% by $1360.92, how much is invested at each rate? (round to two decimal places if necessary.)

Question

$18,887 is invested, part at 14% and the rest at 8%.  If the interest earned from the amount invested at 14% exceeds the interest earned from the amount invested at 8% by $1360.92, how much is invested at each rate? (round to two decimal places if necessary.)

anonymous · Answer

So what is the amount for 14%??

amistre64 · Answer

the part that is not invested at 8% ..

anonymous · Answer

sorry misread the question too :(

anonymous · Answer

x= amount at 14%
18887-x = amount at 8%
.14x=.08(18887-x)+1360.92

amistre64 · Answer

a + b =  18,887

a(.14) = b(.08) + 1360

anonymous · Answer

14x=8(18887-x)+136092
22x=287188
x=13054
other amount  5833

amistre64 · Answer

a + b = t

a = t - b

a(x) = b(y) + r

(t-b)(x) = b(y) + r

tx -bx = by +r

tx-r = by+bx

tx-r = b(y+x)

(tx-r)/(y+x) = b 

18887(.14) - 1360.92
-------------------- = b
         .14 + .08

amistre64 · Answer

5833 = b invested at 8% right?

anonymous · Answer

I am not for sure...  So what amount would be invested at 14%?

anonymous · Answer

13054

amistre64 · Answer

the amount that is not invested at 8% ...

amistre64 · Answer

if you cant subtract by now, there isnt much we can do for you ...