Question

The base of a triangle is 3 centimeters greater than the height. The area is 14cm squared. /find the height and the length if the base.

Answer 1

\[1/2*(x+3)*(x)=14^{2}\]

Answer 2

x^2+3x=28
x^2+3x-28=0
solve

Answer 3

A=bh, and b=h+3. Therefore, 14=h*(h+3), or h^2+3h-14=0. Get yo solve on.

Answer 4

\[14=\frac{(3+h)*h}{2}\]\[14*2=3h+h^2\]\[28=3h+h^2\]\[h^2+3h-28=0\]Factor:(h+7)(h-4)
h= -7 or h= 4
the height can't not negative than the height is : 4
Base = 4+3
Base=7
check: \[\frac{7*4}{2}=\frac{28}{2}=14cm^2\]

Answer 5

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