Prove that sinh(x+y)=sinhxcoshy+sinhycoshx. I've tried it from both side. One way I just get ((e^x)(e^y)-(e^-x)(e^-y))/2 and the other way I just get everything to cancel out and I get 1/2..... Help XD

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anonymous · Answer

uploading a pic in a sec

anonymous · Answer

What really helps is the fact that:
$$e^{x} = \cosh(x)+\sinh(x) $$
and 
$$e^{-x} = \cosh(x)-\sinh(x)$$

anonymous · Answer

Can you see that attachment?

anonymous · Answer

Yeah, that is about as intuitive as proving the quotient rule...

anonymous · Answer

Yeah, its exactly like proving the quotient or product rule lol. It was the only thing i could think of, thankfully it worked out :)

anonymous · Answer

Thank you so much!!!