Question

A train traveling 50 mph left a station 30 minutes before a second train running at 55 mph. How soon did the second train overtake the first?

If 50x represents the distance the slower train travels, then the faster train travels
A.55(x - 0.5)
B.55(x + 0.5)
C.50 + 30x

Answer 1

A train traveling 50 mph left a station 30 minutes before a second train running at 55 mph. How soon did the second train overtake the first?
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1st train DATA:
rate = 50 mph ; time = x hrs ; distance = rt = 50x miles
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2nd train DATA:
rate = 55 mph ; time = (x-(1/2)) hrs ; distance = rt = 55(x-(1/2)) miles
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Equation:
distance = distance
50x = 55(x-(1/2)
50x = 55x - (55/2)
-5x = -55/2
x = 11/2
x = 5 1/2 hrs (time at which the 2nd train overtakes the 1st train)
is A
if I deserve a medal than click good answer,Thank

Answer 2

Thanks Mrs. Lam

Answer 3

urwc