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Mathematics 17 Online
OpenStudy (anonymous):

attached question, answerer(s) get a medal

OpenStudy (anonymous):

OpenStudy (anonymous):

Shaded is Pi/(Pi+1)%, so unshaded is about 25%

OpenStudy (anonymous):

tyvm

OpenStudy (saifoo.khan):

Cool.

OpenStudy (anonymous):

very

OpenStudy (saifoo.khan):

Cold.

OpenStudy (blacksteel):

Emerald, how did you get that answer?

OpenStudy (blacksteel):

I solved it as follows: Assume the shaded shapes are approximately half-circles with radius r. Then the area of the shaded region is 2*pi*r^2. The square in the middle will have side length 2r, so area 4*r^2. Then the total area of the figure is 2*pi*r^2 + 4*r^2 = (2*pi +4)*r^2. Then the unshaded region is 4/(2*pi + 4)% of the figure, or 38.89%, or about 40%.

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