Question

evaluate the integral from pi to 0. sin^4 (3t) dt

Answer 1

sin^4 = sin^2 sin^2 for a start

Answer 2

sin^2 = 1/2-cos(2t)/2 right?

Answer 3

yes

Answer 4

so i did (1/2 (1-cos6t))^2

Answer 5

id have to do it on paper ...

Answer 6

jjiji ok

Answer 7

u = 3t to clear that up .... du = 3 dt; dt = du/3

Answer 8

i cant recall the steps to well at the moment ... but this is what it amounts to:

http://www.wolframalpha.com/input/?i=int%28sin^4%28u%29%2F3%29du