simplify. sqrt of 315x^5. okay I got the next step... 3sqrt35x^5. what do I do with the power in the square root?

Question

anonymous · Answer

$$3\sqrt{35x ^{5}}$$

anonymous · Answer

You divide the power by 2, because you are effectively raising the the initial 315x^5 to the power of 1/2.  So it becomes 3 * sqrt(35) * x ^ (5/2)

anonymous · Answer

$$3\sqrt{35}x ^{5/2}$$

anonymous · Answer

nah just want to know what to do with the power in the root really.

anonymous · Answer

$$(315x ^{5})^{1/2}$$

anonymous · Answer

$$\sqrt{315}*(x ^{5})^{1/2}$$

anonymous · Answer

$$\sqrt{315x ^{5}} = \sqrt{315}*\sqrt{x ^{5}}= \sqrt{3*3*5*7}*\sqrt{x ^{2}*^{2}*x}$$

anonymous · Answer

$$3\sqrt{35}*x ^{2}\sqrt{x}$$

anonymous · Answer

$$3x ^{2}\sqrt{35x}$$

anonymous · Answer

ah, yes, 5 times a half...

$$3\sqrt{35}*x ^{5/2}$$

Ah!!! (again!) halfway...

how did you go from $$\sqrt{x ^{2}*x ^{2}*x}$$

to

anonymous · Answer

oops lol...

$$x ^{2}\sqrt{x}$$

anonymous · Answer

when u have a square number under the root sign u take it out and write it once because root of a square is the number $$\sqrt{4}=\sqrt{2^{2}}=2$$

anonymous · Answer

Ah okay! Perfect! Thanks all!

anonymous · Answer

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