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Find the volume of the solid obtained by rotating the region bounded by the given curves about the specified line. sketch the region and the solid. y=1-x^2, y=0; about the x-axis
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about x axis
\[ V = \pi \int\limits_{a}^{b} y^2 dx \]
\[ V= \pi \int\limits_{a}^{b} ( 1-2x^2 +x^4 ) dx \]
where a<b , and a and b are boundaries on x
y=0 is the x axis :\
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the region is not defined
if x=0 would answer be c + (8pi)/15
:|
what u said makes absolutely no sense, and you included a constant in a definate integral
what would the answer be if boundaries were x=0 and y= 0, and Y= 1- X^2 revolving around x axis
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8pi/15 I guess, without the c :|
u guess? u didnt try to work it out did u. just seein ghow rusty i am
so what is the answer on my question
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