Question

How do you simplify indices? Eg, (4g^2)^3 / 2(32g^2)^2

Answer 1

\[\frac{4g^2\times4g^2\times4g^2}{2\times32g^2\times32g^2} = \frac{2g^2}{64} = \frac{g^2}{32}\]

Answer 2

I don't see how you went from \[4g^2 \times 4g^2 \times 4g^2 \to 2g^2\]
And from \[2 \times 32g^2 \times 32g^2 \to 64\]

Answer 3

I skipped some steps in between. Sorry about that
\[\frac{4g^2\times4g^2\times4g^2}{2\times32g^2\times32g^2} = \frac{2g^2\times g^2\times g^2}{8g^2\times8g^2} = \frac{2g^2}{8\times8} = \frac{2g^2}{64}\]

Answer 4

Cool, thanks :)

Answer 5

No problems :) Hope it help