Simplify the expression using the properties of exponents:
(x^-2y^0)^2(4x^3y^-3)^3
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(3x^0y^2)^2(x^-1y^3)^2

Question

Simplify the expression using the properties of exponents:
(x^-2y^0)^2(4x^3y^-3)^3 
______________________________
(3x^0y^2)^2(x^-1y^3)^2

anonymous · Answer

first step would be to get rid of everything written to the power of 0,  because 
$$b^0=1$$

mathteacher1729 · Answer

Here is the original problem in $\LaTeX$:
$$\frac{(x^{-2}y^0)^2(4x^3y^{-3})^3}{(3x^0y^2)^2(x^{-1}y^3)^2}$$

anonymous · Answer

does ^+3y^-3 mean that the 3y term is raised to that power?

anonymous · Answer

listen to math teach use latex for comples exp.

anonymous · Answer

yes it does

anonymous · Answer

so start with 
$$\frac{(x^{-2})^2(4x^3y^{-3})^3}{(y^2)^2(x^{-1}y^3)^2}$$

anonymous · Answer

no that is a mistake.  need 
$$(3y^2)^2$$ in the denominator sorry

anonymous · Answer

$$(256/9)x^7y^{-19}$$

anonymous · Answer

So 9 is the numerator and 256 is the denominator...  right??

anonymous · Answer

$$(x^4)(64x^9y^-9)$$
$$(9y^4)(x^-2y^6)$$

anonymous · Answer

$$64x ^{13}y^{-9}$$
$$9y^{10}x^{-2}$$

anonymous · Answer

$$64x^{15}$$
$$9y^{19}$$
should be your final answer