Ask your own question, for FREE!
Mathematics 14 Online
OpenStudy (anonymous):

evaluate this integrals;check by differentiation. ʃ dv/v²

OpenStudy (anonymous):

use the power rule backwards

OpenStudy (anonymous):

write it as negative power

OpenStudy (anonymous):

\[\int \frac{dv}{v^2}=\int v^{-2}dv\]

OpenStudy (anonymous):

good from there?

OpenStudy (anonymous):

\[-v + C\]

OpenStudy (anonymous):

\[-v^{-1}+C\]

Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!
Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!