Given: lim g(x)=4, g'(5) = -1 x->5 Continuous at x=5 Find the value of the following; lim [g(x)-g(5)] x->5
I guess my question is whether g(5) = g'(5). I assume not, which leads me to the question: how the heck do you find out the value of g(5)?
It is given that g is continuous at 5. So does not this mean that g(5)=lim as x approaches 5 of g?
would it not mean that you would take the antiderivative of -1 and then plug 5 in which would give you the point 9?
i could be wrong
^ Never done anti-derivatives.
hmm...
I am fairly certain g(5)=4
this would mean the solution is 0
wait is it saying in the given that the lim as x approaches 5 of g(x) is 4? if so then yes i believe the answer is 0 as well
thats what I assumed
that is what it appears to be
giving g'(x)=-1 is just unnecessary information
^ There were six questions given the same information. only needed help with 1/6
So Dong, what you were saying above is g(5) = 5 because the functions are continuous at x=5?
"wait is it saying in the given that the lim as x approaches 5 of g(x) is 4? if so then yes i believe the answer is 0 as well" I missed this post. Yes, it is saying that.
no he is saying that since the limit as x approaches 5 for g(x) is 4 and to get that you have to plug 5 into the equation that you cannot see then by assumption g(5) is the same thing as g(x) based on the limit. that would make the limit as x approaches 5, 4-4
i believe that is what he was saying
Thank you for the clarification and help, both of you :)
no prob! :D
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