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Mathematics 19 Online
OpenStudy (bahrom7893):

Linear algebra help!

OpenStudy (bahrom7893):

Let T be the operator on R^3 defined by: T(x;y;z) = (x-y, y-x,x-z) and consider the vector: \[v = \left(\begin{matrix}1 \\ 1\\2\end{matrix}\right)\] and the basis..

OpenStudy (bahrom7893):

and the basis: B = {(1,0,1), (0,1,1),(1,1,0)}

OpenStudy (bahrom7893):

a) Determine [T]b and [v]b b) Compute [T(v)]b, and then verify that [T]b[v]b = [T(v)]b

OpenStudy (anonymous):

So what don't you know how to do? T of b, v of b, or T of v of b?

OpenStudy (bahrom7893):

actually all of those... i cant find a solved example.. all i need is a solution to a similar example..

OpenStudy (anonymous):

So you want direction rather than a straight up answer?

OpenStudy (bahrom7893):

yes.. not the answer. i have the answers i just want the steps..

OpenStudy (bahrom7893):

my textbook sucks..

OpenStudy (anonymous):

Heard that. Most collegiate math textbooks do. The douche bags that write them are trying to sell you an answer key as well. Lets start with [T]b.

OpenStudy (anonymous):

T is considered a transformation for a given input, in this case, a matrix with three elements. As we will be performing T on b, you will be performing each given T operation on the given b element. What do you think we should do first?

OpenStudy (bahrom7893):

hmm was it something like: (1 0 1)(a1) (1) (0 1 1)(a2)=(1) (1 1 0)(a3) (2)

OpenStudy (anonymous):

I believe what you are thinking of is the linear transformation Ax=B; where you are commonly given A and B and told to solve for x. I don't believe that is what is being asked for here.

OpenStudy (anonymous):

In this case, I don't believe we need v at all to calculate T of b.

OpenStudy (bahrom7893):

i was looking at my example that the professor solved in class: he also had a basis: B = {u1,u2,u3} vector: v = (x1,x2,x3} So then he said that: [v]b = [a1,a2,a3] and [x1,x2,x3] = a1*u1+a2*u2+a3*u3

OpenStudy (bahrom7893):

let me see.. im working this out actually if i get the right answer then so far so good..

OpenStudy (bahrom7893):

heres what he was doin

OpenStudy (anonymous):

Ok. Let me know if the answer for [T]b is {(1,-1,0),(-1,1,0),(0,-1,1)}

OpenStudy (bahrom7893):

[T]b is actually: \[\left[\begin{matrix}1 & -3/2&1/2 \\ -1 & 1/2&1/2\\0&1/2&-1/2 \end{matrix}\right]\]

OpenStudy (bahrom7893):

I got [v]b right, it was: (1,1,0)

OpenStudy (anonymous):

What's the title of your math book?

OpenStudy (bahrom7893):

Matrix Analysis and Applied Linear Algebra by Carl D. Meyer

OpenStudy (anonymous):

Found it. Where are we? Chapter 3? 4?

OpenStudy (bahrom7893):

chapter 4

OpenStudy (bahrom7893):

Excercise 4.7.8

OpenStudy (anonymous):

Sorry. I know how to do this, I'm just unfamiliar with this man's notation. Can you tell me what the square brackets are meant to indicate? I interprated them as parenthesis in your OP.

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