Question

I need help with this simultaneous equation

y = x^2 + 1
2y + 2 = x^2 + 6x

Anyone can show me, the steps? Thanks

Answer 1

first substitute:
2(x^2 + 1) +2= X^2 +6x
2x^2 + 2 + 2 = x^2 + 6x
2x^2 + 4 = x^2 + 6x
x^2 -6x + 4 = 0
then factor... which i dont feel like doing right now.

Answer 2

y = x^2 + 1
y + 2 = x^2 + 6x subtract 2 from both sides
y = x^2 + 6x -2 substitute for y in first equation
x^2 + 6x -2= x^2 + 1 subtrasct x^2 from both sides
6x -2= 1 add 2 to both sides
6x = 3 divide by 6 on both sides
x = 1/2

Answer 3

napervillian: wrong problem again.

Answer 4

y = 5/4

Answer 5

be clear
x = 1/2
y = 5/4

Answer 6

Thanks gianfranco once again !!!, understand it now the process you did it and also thanks elizated :)

Answer 7

Glad to be of help.

Answer 8

One question the second line it says y + 2 but it was 2y

Answer 9

Yea, sorry I was too lazy to finish but Gianfraco saved the day!

Answer 10

Serrico, then my answer is wrong.

Answer 11

y = x^2 + 1
2y = x^2 + 6x
multiply equation 1 by 2
2y = 2x^2 + 2 equate right hand sides
x^2 + 6x = 2x^2 + 2 subtract x^2 from both sides
6x = x^2 + 2 subtract 6x from both sides
0 = x^2 -6x + 2 complete the square
x = 3 -sqrt7 [and y = 3]or x = 3 + sqrt 7[and y = 17]

Answer 12

hahahaha

Answer 13

Thank you again, for taking your time in resolving it again even thought you didn't have too but it makes sense now. Using the square root otherwise I get weird X

Answer 14

its 2y + 2
not only 2y in "2y = x^2 + 6x "

Answer 15

y=x^2 +1
2y+2=x^2+6x
then multiply the first equation by 2, we got
2y=2x^2+2
2y+2=x^2+6x
then substitute 2y in the first equation into the second one
(2x^2+2) + 2 = x^2+6x
2x^2+4 = x^2+6 (subtract x^2 from both sides)
x^2+4=6x
x^2-6x+4=0 (Elizated was right)
then solve x by yourself, M>A>R>C

Answer 16

ELIZATED FTW