how do i know arccos -1/sqrt2 = 3pi/4
\[\theta=\cos^{-1} -1/\sqrt{2} \]
there is a unit circle you should memorize. i'll attach a pic in a sec
this is all stuff they will expect you to have memorized. well, the first and second quadrants atleast
since arccos is the inverse of cosine, you can rewrite the equation as: cos(3pi/4) = -1/sqrt(2). And this is plainly true if you can quickly sketch the cosine function, which you should know.
hm, maybe i should learn it then.... would you just do that by wrote learning? isn't there a slightly easier way (takes slightly less time than wrote?)
the ordered pairs are (cos(theta),sin(theta))
Yes, you should memorize it, though there is a very nice reason why these functions look the way they do.. I would recommend the khan-academy.org website for an in depth explanation
i feel like i should know what an ordered pair is...
ordered pair: (x,y)
oh
gah, khan's voice annoys me.
lol
Paul Zord, what course are you taking?
You never learned unit circle?
its a first year subject
i've learnt it and forgotten it.
If you've learned it before, you can learn it again. It's easy....
paul:one of the great things aboput open study is that it allows you to revise all your basic concepts from ...a time long long ago
Unit circle is based on the fact that the radius of a circle is one and then you can find all of the other angles using triangles, special angles rules and trigonometry
And coverting between radians and degrees is easy because pi = 180 for example: 3pi/4 = 3(180)/4 = 3(45) = 135 degrees
radians = 135*(pi/180)
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