Question

differentiate.

h(t)=t/1-t^2

Answer 1

did u mean t/(1-t^2) ?

Answer 2

yes that is what i meant, sorry for the confusion

Answer 3

okay so use quotient rule:
lodehi take hidelo draw a line and square the lo.. lol

Answer 4

[(1-t^2)*1 - [t(-2t)]] / (1-t^2)^2

Answer 5

[ 1-t^2 + 2t^2 ] / (1-t^2)^2 =
= (t^2+1)/(1-t^2)^2

Answer 6

the minus 2t in the problem is the derivative of 1-t^2, right?

Answer 7

yes.

Answer 8

the question i have is what happens to the 2t^2

Answer 9

2t^2 -t^2 it becomes t^2..

Answer 10

okay that makes sense...
thanks

Answer 11

\[\int\limits_{ }^{}t/1-t^2dt=u=1-t^2 du=-2tdt\]
\[-1/2\int\limits_{}^{}du/u = -1/2\ln(1-t^2)+c\]
looks like on a good day ln(1-t^2)^-1/2+C

Answer 12

i dont know what you guys are doing but this problem is SCEAMING ln