Question

An object is initially at rest and starts to accelerate uniformly at 3 m/s2 at time t = 0 s. At time t = 8 s, what would be the distance travelled by the object?

Answer 1

s = 0.5 x 3 x 8^2

= 96 m

Answer 2

May i know how you get the answer?

Answer 3

X= x0 + v0t+ 1/2 a t^2

Answer 4

s = 0.5aT^2

Answer 5

may i know why do you need the 0.5?

Answer 6

1/2 a t^2

Answer 7

its part of the formula..shall i derive it??

Answer 8

Please. What forumla did you use ?

Answer 9

see
do u know
v = u + at

Answer 10

?

Answer 11

No . I dont.

Answer 12

ohk
dx/dt = v isnt it?

Answer 13

no :P

Answer 14

Oh yeah. I think i know how you got the first one. You re -arranged the acceleration formula ?

Answer 15

yes

Answer 16

so v = u + at

dx/dt = u + at
dx = (u+at)dt

Answer 17

now integrate both sides

Answer 18

wt do u get?

Answer 19

1

Answer 20

I never learn integrate ?

Answer 21

you dont need the displacement function anyway newbs

Answer 22

ohk never mind

u get

x = ut + 0.5 at^2

ull understand when u learn integration

Answer 23

v= 3t

since it is always moving in the same direction

distance =\[\int\limits_{0}^{8} 3t dt \]

Answer 24

= (3/2) 8^2

Answer 25

3 x 32 = 96m