Use the vector product to find the area of the triangle PQR, P = (5,1,1), Q = (2,−1,3) and R = (−1,4,2).
do you know what the answer is already? i got 1.5, not sure if what im going is right though. Doesnt sound right lol
find vector pq and pr take the dot product of the two the cross product will give you the volume
its 12.1 or so.... but im stuck on the easiest bit...
well not the easiest, just getting the vectors pq and pr
find the magnitude of the cross product between PQ and PR. This will give you the area of the parallelogram. Divide this by 2 and you will get the area of the triangle.
you would subtract the coordinates of p from q to get vector pq, same for pr
=1/2((pq.pq)(pr.pr)-(pq.pr)^2)^1/2 =1/2(17x46-14^2^1/2)=12.1
oh ok well the solutions i have are wrong then for this question;.
partly wrong... .thanks guys/
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