It takes a force of 78.0 N to compress the spring of a toy popgun 0.201 m to "load" a 0.145 kg ball. With what speed will the ball leave the gun? can anyone help me please
First assume that all of the potential energy of the spring is transformed into kinetic energy of the ball.
yeah but i just dont know how to do it at all im completely lost i just need the answer
Calculate the amount of kinetic energy the ball receives.
cant you give me the answer
please
W = Fs = E E = .5mv^2 <=> v = sqrt(E/.5m) v = sqrt(Fs/.5m) v = sqrt(78.0N*.201m/(.5*.145)) = 14.7053825 m / s approximately 15m/s
Actually 14.7 m/s is fine.
oh ok let me put it online
no it did not work
i plugged it my homework online
It should be the correct answer. Try changing the rounding.
Oh wait, is this a maths or a physics problem?
physics
in that case i don't see what's wrong with it.
i dont know
can u solve another problem like that one just with different numbers
to see if it works online
this should be extremely simple. see if someone else gets a different result.
no one has tried it only you
hello help plz
is the gun vertical or horizontal? this matters. Lets assume gun is being fired horizontally PE_i + KE_i = PE_f + KE_f PE_i = 1/2 k x^2 KE_i = 0 ball is not moving PE_f = 0 spring is not being compressed KE_f = 1/2 m v^2
therefore PE_i = KE_f
plz the answer
v = sqrt(Fx/m) v = 10.398275719129325085729820157569 answer is wrong if being fired vertically
wait the one you gave me now is wrong ???
Isn't it v = sqrt(Fx/.5m) Because E=.5mv^2 <=> v = sqrt(E/.5m) ?
thank you so much the duke you are right
no answer depend on how the item is fired
i was trying all night to get it thank you so much duke i truly appreciate it
Zuige you mistake is the energy is not constant for a spring the spring energy is 1/2 k x^2 so the work is not simply force times displacement to get energy
oh, of course. sorry for the mistake!
thank u so much to all
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