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For the points (0,0) and (x,-4) find x so that the distance between the points is 5.
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\[\sqrt{(x-0)^2+(-4-0)^2}\]
=5
25=x^2+16 25-16=x^2 x^2=9 x=3
y answer ur own question? haha..
just checking it, i realized when i did it and check back it was correct but i already posted it so i said i will finish it
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Hi pirplec16 .. The work done by you is correct but not complete. The answer is \[\pm 3\]
what sgad says is true x=3 or x=-3
yeah i was wondering if i should put +/- three thanks myininaya!
\[Let A(x _{1};y _{1}) and B(x_{2};y_{2})\] be 2 points.Then,the distance between them is \[\sqrt{(x_{2}-x_{1})^{2}-(y_{2}-y_{1})^{2}}\]
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