derivative of n^2?
n is integer
hmmm - i think u know already
2n
derivative is {3,5,7,9} derivative is \[2n+1\]
If the function is: \[f(x) = ax^n\] The derivative of any function is basically: n*ax^(n-1)
Therefore, d/dx n^2 = 2n
That's only for continuous function
n^2 is continuous.
Oh, I see what you mean. Yeah, I should have put that in, I forgot. Sorry. Here, the derivative of any CONTINUOUS function is n*ax^(n-1)
n is set of integer n={1,2,3,4,5} n^2={1,4,9,16,25} derivative is {3,5,7,9}=2n+1
Derivative = 2n NOT +1
Yes it is 2n for n^2 continuous function; not for discreet
derivative wrt what? do you mean discrete differentiation?
if so this is not really a "derivative' just a formula for differences. {1,4,9,16,25...} differences are {3,5,7,...} so you either get 2n-1 or 2n+1 depending on which direction you are going
derivative wrt its place
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