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Mathematics 16 Online
OpenStudy (anonymous):

derivative of n^2?

OpenStudy (anonymous):

n is integer

OpenStudy (anonymous):

hmmm - i think u know already

OpenStudy (anonymous):

2n

OpenStudy (anonymous):

derivative is {3,5,7,9} derivative is \[2n+1\]

OpenStudy (anonymous):

If the function is: \[f(x) = ax^n\] The derivative of any function is basically: n*ax^(n-1)

OpenStudy (anonymous):

Therefore, d/dx n^2 = 2n

OpenStudy (anonymous):

That's only for continuous function

OpenStudy (anonymous):

n^2 is continuous.

OpenStudy (anonymous):

Oh, I see what you mean. Yeah, I should have put that in, I forgot. Sorry. Here, the derivative of any CONTINUOUS function is n*ax^(n-1)

OpenStudy (anonymous):

n is set of integer n={1,2,3,4,5} n^2={1,4,9,16,25} derivative is {3,5,7,9}=2n+1

OpenStudy (anonymous):

Derivative = 2n NOT +1

OpenStudy (anonymous):

Yes it is 2n for n^2 continuous function; not for discreet

OpenStudy (anonymous):

derivative wrt what? do you mean discrete differentiation?

OpenStudy (anonymous):

if so this is not really a "derivative' just a formula for differences. {1,4,9,16,25...} differences are {3,5,7,...} so you either get 2n-1 or 2n+1 depending on which direction you are going

OpenStudy (anonymous):

derivative wrt its place

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