Question

In a 45-45-90 triangle, the hypotenuse is 18.56 cm. Find the length of the leg.
13.21 cm
13.12 cm
26.25 cm
26.52 cm
.

Answer 1

18.56cos45=13.12 cm

Answer 2

For a 45-45-90 triangle the lengths of the legs are the same. Therefore,
\[\ell^2+\ell^2=h^2\Rightarrow 2\cdot\ell^2=h^2\Rightarrow\sqrt{2}\ell=h\Rightarrow\ell=\frac{h}{\sqrt{2}}\]

\[\ell=\frac{18.56}{\sqrt{2}}\approx13.12\]

Answer 3

thanks so much :)