Question

attached question, answerer(s) get a medal!

Answer 1

sorry, no Circle Probs. :/

Answer 2

aw :(

Answer 3

equation 4 a circle:
(x-k)^2+(y-h)^2=r^2
center (k,h)
radius is r

Answer 4

Thanks, could you walk me through the problem? It's sorta confusing.

Answer 5

the k and h is the amount of offset the center of the circle is from (0,0)

Answer 6

radar when u get a chance, take a look at my linear algebra problem PLEASE!!!!!!!

Answer 7

yea so whatever the k and h amounts are, are the values of the center of the circle. think of the k and h as shifts from the origin

Answer 8

Your circle is not centered at (0,0)

Answer 9

But you have been provided information needed to calculate k and h

Answer 10

alright, but how? I just don't understand how I put the numbers together

Answer 11

Have you looked closely at the formula that jahtoday provided.

Answer 12

so k = 9 and h = 3?

Answer 13

If they gave u a problem that said there's a circle with radius r and its center is (k,h) then the equation for the circle would b
\[(x-k)^2+(y-h)^2=r^2\]

Answer 14

ugh, i looked at the wrong problem. disgregard that last reply

Answer 15

okay, so does the problem looks like this: (x - -10)^2 + (y - 6)^2?

Answer 16

similarly they gave u that the center is (-10,6) with radius 8
so the equation would b
\[(x+10)^2+(y-6)^2=8^2\]

Answer 17

yes

Answer 18

alright.. so how do i find the answers for the questions in parentheses?

Answer 19

i'm not seeing any questions in parentheses. what do u mean

Answer 20

oh, the answer is that equation? Wow, thanks!