Question

Find all values of k that ensure that the given equation has exactly one solution.
4x2 + kx + 49 = 0
What is:
k = ____ (smaller value)
k = ____ (larger value)

Answer 1

k^2 -4(4)(49) =0

Answer 2

solve , you will get one positive and one negative , thus the largest and smallest

Answer 3

k^2 - (4^2 )(7^2) = 0

k ^2 - 28^2 =0

k=+-28

Answer 4

being a pro without a calculator :D

Answer 5

make sure
\[b^2-4ac=0\] with
\[a=4,b=k,c=49\]

Answer 6

\[k^2-4\times 4 \times 49=0\]
\[k^2-4^2\times 7^2=0\]
\[k^2=4^2\times 7^2\]
\[k=\pm 4\times 7\]
\[k= \pm 28\]

Answer 7

what elecengineer wrote!