Question

find the value of h and k that makes the equation true
x^2+4x= (x-h)^2 + k

Answer 1

h=-2
k=-4

Answer 2

or h=0
k=4x

Answer 3

how'd you get the answer jahtoday?

Answer 4

re-write your equation as:
\[x ^{2}+4x=x ^{2}-2hx+h ^{2}+k\]
then:
\[4x=x* (-2h) +(k+h ^{2})\]
in order left side = right one, we need what...?

Answer 5

exactly

Answer 6

4=-2h , which gives: h=-2
and k+h^2=0, which will give you:
k=-4

Answer 7

oooh okay..