A particle travels 16 times around a 18-cm radius circle in 37 seconds. What is the average velocity (in m/s) of the particle?
oh jeeze. 2 different answers lol
and they're gone...
so T is period right? and a period is how long it takes for one revolution so 37/16=2.3125
and V=2pir/T I think
Average velocity is displacement over time. Since the particle ends in the same spot as it started its average velocity is 0. If you're looking for average speed it would be total distance traveled over time: \[D=(2π∗r)*16=2∗3.14∗18*16=1808cm=18.08m\] V=D/t=18.08/37=.489m/s
so V=((2)(pi)(18))/2.3125
am I wrong?
V=48.9
I just need confirmation that I'm doing it right lol
I think I did it right, I just forgot to convert cm to m
If you are finding average speed, yes you're doing it right (except check your units). Average velocity would be 0 m/s
so the answer is .489 m/s?
Thank you!
\[V=r \omega\] \[\omega =(16*2\pi)\div37 =2.7 radians/\sec\] \[r=0.18 m\] \[Velocity, V=0.18*2.7=0.486m/s\]
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