Ask your own question, for FREE!
Mathematics 21 Online
OpenStudy (anonymous):

Determine if the series is absolutely convergent, conditionally convergent, or divergent. \[\sum_{2}^{\infty}n \div \left( \ln n \right)^{n}\]

OpenStudy (zarkon):

Absolutely convergent...use root test

OpenStudy (anonymous):

how do u use the root test, I'm still confused about it

OpenStudy (anonymous):

\begin{eqnarray*}\limsup_{n\to\infty}\left(\sqrt[n]{\frac{n}{\log^n(n)}}\right)&=&\limsup_{n\to\infty}\left(\frac{\sqrt[n]{n}}{\log(n)}\right)\\&=&\lim_{n\to\infty}\left(\frac{\sqrt[n]{n}}{\log(n)}\right)\\&=& 0.\end{eqnarray*}Because this number is less than 1, the series is absolutely convergent.

Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!
Latest Questions
Breathless: Spooky witch but cute
4 hours ago 3 Replies 0 Medals
Arriyanalol: help
3 hours ago 10 Replies 2 Medals
Arriyanalol: @tinydinoUwU stop trying to find a argument u blad lil boy
1 day ago 5 Replies 3 Medals
Jaded012023: Please tell me what you all think of this song
6 hours ago 6 Replies 1 Medal
Arriyanalol: bro how
6 hours ago 2 Replies 3 Medals
Arriyanalol: cant wait for the new bluey movie in 2027
1 day ago 12 Replies 2 Medals
Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!