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Mathematics 14 Online
OpenStudy (anonymous):

atach file ,I need help check my answer number 4 and 5 only,

OpenStudy (anonymous):

OpenStudy (anonymous):

for #4 you are given the equation \[v=\sqrt{2(h*g)}\] and it ask that you solve in for h in terms of v which looks like....

OpenStudy (anonymous):

\[(v^2)/g=h\]

myininaya (myininaya):

your 2 this appeared

myininaya (myininaya):

omg i hate english disappeared lol

OpenStudy (anonymous):

the key 5) is yes , the advertised pump will reach a maximum height of 87.9 ft

OpenStudy (anonymous):

the answer to #5 is yes it will because if you use our equation from before you end up with a pump that will not only go up to 80 feet in the air but it will project it into the air 175.78 feet.

OpenStudy (anonymous):

how u get the answer can u write equation

OpenStudy (anonymous):

for number five you can just show the math. 75^2/32=175 where 75= the pumps velocity and 32= the acceleration due to gravity

OpenStudy (anonymous):

thats how high the pump in problem #5 will pump, the max height that is.

OpenStudy (anonymous):

sorry the key is 87.9 ft

myininaya (myininaya):

he is missing 2 in the denominator

myininaya (myininaya):

75^2/(2*32)

OpenStudy (anonymous):

great thank

myininaya (myininaya):

h=v^2/(2*g)

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