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Find the equation of the parabola determined by the condition: Axis horizontal, focus (0,0), latus rectum 8. Would someone kindly help me please? :)) Would gladly appreciated.
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so a=4
focal length is 4
the vertex is ( 4,0 )
(y-k)^2 = -4a(x-h)
y^2 = - 16(x-4)
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if the latus rectum is x=8 , then the distance from the latus rectum to the focus is twice the focal length
I see... :)
also, since the focus is always "inside " the parabola, you know the parabola opens to the left
noted.
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