Find the derivative of the function. Simplify if possible. y = arcsin(4x + 2)
the derivitive rule for arcsin is (1/sqrt(1-x^2))
4/ somethin :)
of course you will also need the chain rule. so you have dy/dx=4/sqrt(1-(4x-2)^2))
4 comes from chain rule and you just throw in 4x+2 as x
that was wrong
i think because you put a minus sign..instead of a plus sign
yes that was the problem...I got it right now
yeah sorry +
yes thanks its right!
no problem. good luck
can you help with one more?
sure
Find the derivative of the function. Simplify if possible. \[y=\sqrt{13\arctan x}\]
okay. so this is the same as saying (13arctanx)^1/2
so first we bring down that half right? and we get (13/2)*(1/sqrt(arctan(x))*(1/(x^2+1)) let me check my work real quick
wait majorly screwed it up
LOL
ok step1 power rule (1/2)*1/(sqrt(13arctan(x)) step2 chain rule (1/2)*1/(sqrt(13arctan(x))*(13/(x^2+1)) simplify 13/((x^2-1)sqrt(13arctan(x)) but wolfram seems to disagree
sorry wolfram doesnt disagree. they just rationalized their denominator
what is wolfram?
www.wolframalpha.com <-- will literally solve anything you type in there
13/(2(x^2+1)sqrt(13arctan(x)) there ya go missed the 1/2 i started out with:) hard to keep track when im typing this stuff
so just to clear it up. (1/2) is pulled down from sqrt with power rule which also moved the sqrt(13arctanx) to the bottom. then chain rule we derive 13arctan to get that 13 on top and x^2+1 on bottom
WOW THAT WEBSITE IS GREAT!!!
it understands most verbage. you can type derive x^2+5 or solve 3x^3+4x^2+3x+5=0 and it should have no problem
integrate whatever etc
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