Question

I need help!!!! solving ^3square root 2^3x =3/2

Answer 1

I just want to make sure I'm reading this right... The problem is:
[cube root of (2^(3x))] = 3/2
I'm not quite clear on what the problem is the way you wrote it...

Answer 2

you should use paranethesis to indicate what is under the radical.

3rt(stuff under) is easier to understand

Answer 3

cube root of 3^6 x^3 =3/2

Answer 4

cbrt(3^6 * x^3) = 3/2 ; uncube the left side

3^2 * x = 3/2 ; divide out the 3^2

x = 3/2/(9) = 3/18 = 1/6 .. maybe

Answer 5

First, start out by cubing both sides. This gives you
3^6 * x^3 = 27/8
Divide both sides by 3^6, which leaves:
x^3 = 1 / (3^3 * 2^3)
Then take the cube root of both sides for the answer:
x = 1/(3*2) = 1/6.

Answer 6

thank you