Question

i need HELP solving this equation!!! 5^a 1^a/4 - 2/2^a = 0

Answer 1

\[\frac{5^a1^a}{4}-\frac{2}{2^a}=0\]
is this right?

Answer 2

yes

Answer 3

1^a=1
so we have
\[\frac{5^a}{4}-\frac{2}{2^a}=0\]

Answer 4

ok

Answer 5

\[\frac{5^a}{4}=\frac{2}{2^a}\]
cross multiply
\[5^a*2^a=2*4\]
\[(5*2)^a=8\]
\[10^a=8\]
take log_10 on both sides (and i will just call it log)
\[\log10^a=\log8\]
\[alog10=\log8\]
\[a=\frac{\log8}{\log10}\]