Question

Anyone know how to solve this? (2y)-3= ????

Answer 1

Incomplete info, re-read question

Answer 2

\[\implies 2y = ???? + 3\]\[\implies y = {???? + 3 \over 2}\]

Answer 3

Sorry! x=6, y=5, z=1/2 this is evaluating expressions.

Answer 4

For 'evaluating' you just plug in the value you are given for the variable.

Answer 5

i guess ur ???? will in most general sense be 0
so (2y)-3=0 will give y=3/2
or as polpak said y= (?????+3)/2

Answer 6

So
\[2y - 3\]\[=2(5)-3\]\[ = 10-3\]
... etc

Answer 7

Oh! Got it. Thanks!

Answer 8

But 10 minus 3 is seven. Why would the answer be zero?

Answer 9

It's not.

Answer 10

...................

Answer 11

So where did the zero come from in the beginning?

Answer 12

What 0?

Answer 13

The K dude said something about my '?????' being zero

Answer 14

I have no idea. In this case your ??? was a 7

Answer 15

i meant most equations take the form of say 2y-3=0
and definitely not 2y-3 =??????

Answer 16

.........Okay. Thanks

Answer 17

@satellite73: What?

Answer 18

y= 3/2