Trigonometry Question, Law of Sines Picture How to do this?
this is gonna be a stupid question but the length 110 ft is that whole leg right?
i believes the antenna on top of the hill so its only part
ok thanks
\[\sin(1.5)/110 = \sin(25)/x\]
the answer is 1600 ft according to the book i dont think thats right
that equation = 1776
I get 1589.326455
how? thats (110 x sin(25)) / sin1.5 or am I doing that wrong?
if you let y=length of the line to the top of the hill. then y=x/sin(25) also by the law of sines...sin(1.5)/110=sin(63.5)/y solve for y gives y=[sin(63.5)/sin(1.5)]*110 [the 63.5 is 90-(25+1.5)] now equate the two versions of y x/sin(25)=[sin(63.5)/sin(1.5)]*110 so x=[sin(25)*sin(63.5)/sin(1.5)]*110
my x is the h in the problem
how did you know to do 90-26.5
the sum of the angles is 180deg ...we already have a right angle so the other two angles must add to 90
hard to download into my brain xD
I did it a 2nd way without the law of sines \[\frac{110+h}{\tan(26.5)}=\frac{x}{\tan(25)}\] now solve for \[x\] this just uses the fact that tangent is opp/adj two times
hm thanks a bunch ill will study this
oops...the x's should be h's
Nice to see degrees instead of radians for a change:-)
I like radians better, but I figured I'd stick to what the problem has given.
1.5 degrees in radians?
why not :)
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