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Mathematics 16 Online
OpenStudy (anonymous):

Trigonometry Question, Law of Sines Picture How to do this?

OpenStudy (anonymous):

myininaya (myininaya):

this is gonna be a stupid question but the length 110 ft is that whole leg right?

OpenStudy (anonymous):

i believes the antenna on top of the hill so its only part

myininaya (myininaya):

ok thanks

OpenStudy (anonymous):

\[\sin(1.5)/110 = \sin(25)/x\]

OpenStudy (anonymous):

the answer is 1600 ft according to the book i dont think thats right

OpenStudy (anonymous):

that equation = 1776

OpenStudy (zarkon):

I get 1589.326455

OpenStudy (anonymous):

how? thats (110 x sin(25)) / sin1.5 or am I doing that wrong?

OpenStudy (zarkon):

if you let y=length of the line to the top of the hill. then y=x/sin(25) also by the law of sines...sin(1.5)/110=sin(63.5)/y solve for y gives y=[sin(63.5)/sin(1.5)]*110 [the 63.5 is 90-(25+1.5)] now equate the two versions of y x/sin(25)=[sin(63.5)/sin(1.5)]*110 so x=[sin(25)*sin(63.5)/sin(1.5)]*110

OpenStudy (zarkon):

my x is the h in the problem

OpenStudy (anonymous):

how did you know to do 90-26.5

OpenStudy (zarkon):

the sum of the angles is 180deg ...we already have a right angle so the other two angles must add to 90

OpenStudy (anonymous):

hard to download into my brain xD

OpenStudy (zarkon):

I did it a 2nd way without the law of sines \[\frac{110+h}{\tan(26.5)}=\frac{x}{\tan(25)}\] now solve for \[x\] this just uses the fact that tangent is opp/adj two times

OpenStudy (anonymous):

hm thanks a bunch ill will study this

OpenStudy (zarkon):

oops...the x's should be h's

OpenStudy (anonymous):

Nice to see degrees instead of radians for a change:-)

OpenStudy (zarkon):

I like radians better, but I figured I'd stick to what the problem has given.

OpenStudy (anonymous):

1.5 degrees in radians?

OpenStudy (zarkon):

why not :)

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