simplify by removing factors of 1 t^2-16/(t+4)^2
\[\frac{t^2-16}{(t+4)^2}\] \[\frac{(t+4)(t-4)}{(t+4)(t+4)}\] now cancel and you are done
cancel what??? sorry very confused
is it gonna be t-4/t+4??
yes
you have a "common factor" of t+4 in numerator an denominator. that is what it means by simplify by removing factors of 1 because \[\frac{t+4}{t+4}=1\]
ok... thanks so much.. can you help me with one more
dont forget that \[\frac{(t+4)(t-4)}{(t+4)(t+4)}=\frac{t+4}{t+4}\times \frac{t-4}{t+4}=1\times \frac{t-4}{t+4}\]
sure ask
find all the numbers for which the rational expression is undefined (t^3-2t)/(t^2-49)
set the denominator = 0 and solve. then say "all numbers except..."
\[t^2-49=0\] \[t^2=49\] \[t=\pm\sqrt{49}\] \[t=7\] \[t=-7\] so all real numbers except those
so i put 7,-7?
or if you prefer \[t^2-49=0\]\[(t+7)(t-7)=0\] \[t=-7\] or \[t=7\] either way
yes the way the question is worded it asks for what is not allowed. so the answer is -7 and 7 are not allowed
thanks so much.. I am having some problems with my math final
good luck!
thanks
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