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OpenStudy (anonymous):
\[\frac{t^2-16}{(t+4)^2}\]
\[\frac{(t+4)(t-4)}{(t+4)(t+4)}\] now cancel and you are done
OpenStudy (anonymous):
cancel what??? sorry very confused
OpenStudy (anonymous):
is it gonna be t-4/t+4??
OpenStudy (anonymous):
yes
OpenStudy (anonymous):
you have a "common factor" of t+4 in numerator an denominator. that is what it means by simplify by removing factors of 1 because
\[\frac{t+4}{t+4}=1\]
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OpenStudy (anonymous):
ok... thanks so much..
can you help me with one more
OpenStudy (anonymous):
dont forget that
\[\frac{(t+4)(t-4)}{(t+4)(t+4)}=\frac{t+4}{t+4}\times \frac{t-4}{t+4}=1\times \frac{t-4}{t+4}\]
OpenStudy (anonymous):
sure ask
OpenStudy (anonymous):
find all the numbers for which the rational expression is undefined (t^3-2t)/(t^2-49)
OpenStudy (anonymous):
set the denominator = 0 and solve. then say "all numbers except..."
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OpenStudy (anonymous):
\[t^2-49=0\]
\[t^2=49\]
\[t=\pm\sqrt{49}\]
\[t=7\]
\[t=-7\] so all real numbers except those
OpenStudy (anonymous):
so i put 7,-7?
OpenStudy (anonymous):
or if you prefer
\[t^2-49=0\]\[(t+7)(t-7)=0\]
\[t=-7\] or
\[t=7\] either way
OpenStudy (anonymous):
yes the way the question is worded it asks for what is not allowed. so the answer is -7 and 7 are not allowed
OpenStudy (anonymous):
thanks so much.. I am having some problems with my math final
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