Question

Find the general form of the equation of the the circle.

Center at the point (-4, -3); containing the point (-3, 3)

Answer 1

general form is
\[(x-h)^2+(y-k)^2=r^2\] so you will have
\[(x+4)^2+(y+3)^2=r^2\] and now you just need
\[r^2\]

Answer 2

to find it find the square of the distance between these point. i t is
\[r^2=(-4+3)^2+(-3-3)^2=1+36=37\] so y our answer is
\[(x+4)^2+(y+3)^2=37\]