Question

Can someone help me solve this problem 10^2x - 2 = 10^x

Answer 1

quadratic eq.

u want to factor it or want the values of x?

Answer 2

value of x

Answer 3

\[10^{2x}-10^x-2=0\] as saifoo said a quadratic in
\[10^x\]

Answer 4

x = 1.17

x = -0.17

Answer 5

can you explain saifoo

Answer 6

u should solve it with the quadratic formula.
As u r going to insert the values, u will automatically arrive to this answer.

Answer 7

solve this as
\[z^2-z-2=0\]

Answer 8

where
\[z=10^x\]

Answer 9

get
\[(z-2)(z+1)=0\]
\[z=2\]
\[z=-1\]

Answer 10

so you have
\[10^x=2\]
\[x=\log(2)\] or
\[10^x=-1\] which has no solution

Answer 11

ok, thank you

Answer 12

not sure what
\[\log(2)\] is but you can find it with a calculator. you do not need the quadratic formula for this because it factors

Answer 13

yw

Answer 14

\[10^{2x} - 2 = 10^{x} <=> (10^{x})^2 - 10^x - 2 = 0\]\[z = 1o^x\]
so \[z^2 - z - 2 = 0\]

the solutions are z = 4 and z = -2
\[10^x = 4 \]and \[10^x = -2\]the second equation has no solution
10^x = 4 => x=log4